Since I was looking into straight O2 injection, I decided to expand my stuidies. Hydrogen peroxide seems promising. I already have a methanol/water injection system, so using H2O2 would be a matter of just pouring some in.
Note: If you didn't know, 35% or 50% hydrogen peroxide is available. This is not for drug store H2O2, that's only 3% usually (way too weak).
Concept:
Use a mix of about 18% H202, 50% methanol, and 32% water. This will be delivered at a flow rate of about .6GPM. By my rough calculations, this will be about the same extra oxygen as a 70HP shot of nitrous. No additional fueling will be needed, as the methanol is already there to react with the extra oxygen. The by product of this combustion will just be heat, CO2, and H20.
Concerns:
Decomposition #1: Will methanol cause rapid decomposition of the H2O2?
Decomposition #2: When in the engine process is the H2O2 likely to decompose? Ideally, it would be during combustion. H2O2 decomposition is exothermic and the extra energy released would be harnessed to create power. If the H2O2 decomposition happens during compression, that energy would be counterproductive. Additionally, if enough heat energy is released, it could actually trigger pre-ignition of the present fuels (gasoline, methanol). I doubt pre-ignition, as there is significant water and methanol to absorb the energy through vaporization, and H2O2 decomposition has been described as a less than powerful reaction, and that was in 90% concentrations. But still, I have to be sure that won't happen, as if it did, it could break parts almost instantly.
Update: Found out the heat of decomposition of H2O2. It's 700 cal/gm, or 1261 BTU/lb. Compare this to gasoline that releases about 20000 BTU/lb when burned. So the energy released directly by H2O2 during decomposition, has only about 6% of the energy as gasoline. Not much, as expected. Plus there will only be about 1.25 lb/min of actual H2O2 in the above example. That's equivalent to 4.5 lb/hr of gasoline, or about 10HP. So if the H2O2 decomposition happens where we want it (combustion), we get a "free" 10HP. If it happens before, is 10HP of heat enough to light off the mix and go ka boom? Or just vaporize some extra water?
Note: If you didn't know, 35% or 50% hydrogen peroxide is available. This is not for drug store H2O2, that's only 3% usually (way too weak).
Concept:
Use a mix of about 18% H202, 50% methanol, and 32% water. This will be delivered at a flow rate of about .6GPM. By my rough calculations, this will be about the same extra oxygen as a 70HP shot of nitrous. No additional fueling will be needed, as the methanol is already there to react with the extra oxygen. The by product of this combustion will just be heat, CO2, and H20.
Concerns:
Decomposition #1: Will methanol cause rapid decomposition of the H2O2?
Decomposition #2: When in the engine process is the H2O2 likely to decompose? Ideally, it would be during combustion. H2O2 decomposition is exothermic and the extra energy released would be harnessed to create power. If the H2O2 decomposition happens during compression, that energy would be counterproductive. Additionally, if enough heat energy is released, it could actually trigger pre-ignition of the present fuels (gasoline, methanol). I doubt pre-ignition, as there is significant water and methanol to absorb the energy through vaporization, and H2O2 decomposition has been described as a less than powerful reaction, and that was in 90% concentrations. But still, I have to be sure that won't happen, as if it did, it could break parts almost instantly.
Update: Found out the heat of decomposition of H2O2. It's 700 cal/gm, or 1261 BTU/lb. Compare this to gasoline that releases about 20000 BTU/lb when burned. So the energy released directly by H2O2 during decomposition, has only about 6% of the energy as gasoline. Not much, as expected. Plus there will only be about 1.25 lb/min of actual H2O2 in the above example. That's equivalent to 4.5 lb/hr of gasoline, or about 10HP. So if the H2O2 decomposition happens where we want it (combustion), we get a "free" 10HP. If it happens before, is 10HP of heat enough to light off the mix and go ka boom? Or just vaporize some extra water?
