In roulette if you are betting on one of the 12's(1st 12, 2nd 12, or 3rd 12) and you stay on the same 12 until a win, how many times in 10,000 spins will you encounter a losing streak of 17 or more (on average)?
You would have a 3% chance (.03) of hitting "A" number on a 38 number wheel. So in 100 spins, theoretically, you should hit the number 3 times. I don't know of any formula to figure out 17x without hitting. But I am not a genius either. :biggrin:
Roulette is a game of chance, in theory. So, every spin is completely independent from the previous spin and has a little under a third chance of hitting the 12 number square since the 0 and 00 do add to the odds.
At the casino one time a friend and i were playing black jack when he noticed that the roulette display screen showed all red hits. Red had been hit or 15 times in a row. He says "WOW black is due" i told him not to bother but he went over anyway. After betting on black and losing 7 times in a row he came back all upset.