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Now the question that I'm dying to know the answer to.
Let's take a compressor that is operating at a pressure ratio of 2 to one. The air entering the turbo has the normal content of oxygen that is in the air all around us. The oxygen content is twice as much per cylinder volume after the compressor. Keeping the math simple and not taking into consideration the temperature rise. Is this correct? If so, then if we start with an air mix that has a higher percentage of oxygen in it and run it through the compressor, have we still doubled the oxygen content per cylinder volume? Keeping heat out of the equation for now. I am in desperate need of some math wizards on this one.
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Donnie Wang
1984 BUICK Grand National with a baaad alcohol and nitrous chaser habit.
100% Methyl Alcohol Injected/ Nitrous Oxide Assisted/ Forced Inductions FI91X Turbocharged/ TA blocked/ M&A headed/ DRW TH475 Transmission/ Neal Chance Pro Mod Torque Converter/ Moser 12 Bolt Rear Axle Housing
Warning: Do not try this at home without proper adult supervision.
Ultimate Stage I BUICK V6 v3.2
GN details
9.19@145 from a 224 CID
5.73@122.1 in the 1/8 mile. Latest best.
1.28 60 foot.
'Perseverence is the key to innovations endless possibilities and varieties locked within each of us.'
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